设 \(X\) 上的测度 \(\mu\) 是函数 \(\mu: \Sigma \to [0,\infty]\),其中 \(\Sigma\) 是 \(\sigma\)-代数,满足: - \(\mu(\emptyset) = 0\) - 可数可加性:\(\mu(\bigcup_i E_i) = \sum_i \mu(E_i)\),其中 \(E_i\) 两两不相交
在 \(\mathbb{R}^n\) 上,Lebesgue 测度 \(\lambda\) 满足: - 平移不变性:\(\lambda(E + x) = \lambda(E)\) - 可数可加性 - \(\lambda([0,1]^n) = 1\)
\(f: X \to \overline{\mathbb{R}}\) 是可测的,若 \(f^{-1}((a,\infty]) \in \Sigma\) 对所有 \(a \in \mathbb{R}\) 成立。
\[\int_X f \, d\mu = \int_0^\infty \mu(\{x: f(x) > t\}) \, dt\]
若 \(0 \leq f_n \uparrow f\) 逐点成立,则: \[\lim \int f_n \, d\mu = \int f \, d\mu\]
若 \(f_n \to f\) 几乎处处且 \(|f_n| \leq g\),其中 \(g \in L^1\),则: \[\lim \int f_n \, d\mu = \int f \, d\mu\]
\[\|f\|_p = \left(\int |f|^p \, d\mu\right)^{1/p}, \quad 1 \leq p < \infty\]
\((X \times Y, \Sigma \otimes \tau, \mu \times \nu)\),满足: \[(\mu \times \nu)(A \times B) = \mu(A)\nu(B)\]
Fubini 定理:\(\int_{X \times Y} f \, d(\mu \times \nu) = \int_X \int_Y f \, d\nu \, d\mu\)